crosswind speed calculator

Time   8 Without using the calculator What is the boat velocity? Insert the numbers from the problem into this equation: Airplane Velocity   440 (850 × -12) + 850 pv = (750 × 12) + 750 pv Each day, a boat makes a 30 mile trip upstream and 30 miles downstream, taking 8 hours for the round trip. Putting this amount into this equation: 30 + [ 30 • (bv -5) ÷ (bv + 5) ] = 8bv -40 4*plane vel + 160 = 4.5 * plane vel - 180 Each day, a boat makes a 30 mile trip upstream and 30 miles downstream, taking 8 hours for the round trip. The shorter method: kumar43251. boat velocity = 10 miles per hour, Clicking "Calculate" we see the answers are: Distance 1   725 plane velocity = 192 To calculate a crosswind component, you must know the wind direction, speed, and runway heading. (850 × -12) + 850 pv = (750 × 12) + 750 pv Using the calculator, we click "F" then enter [ 30 • (bv -5) ÷ (bv + 5) ] = 8bv -70 [ 30 ÷ (bv - 5) ] + [ 30 ÷ (bv + 5) ] = 8 Wind (or Current) Velocity   5, Clicking "Calculate" we see the answer is: The velocity of the current is 5 miles per hour. What is the boat velocity? We'll also abbreviate plane velocity and wind velocity as pv and wv. Each day, a boat makes a 30 mile trip upstream and 30 miles downstream, taking 8 hours for the round trip. Distance 2   750 It is found in only one other place online, where it is scheduled for deletion. (152,250 -141,750) ÷ 1,400 = wind velocity Dist (out) = (plane vel + 40) * 4 Entering Distance 1 = 750 and Distance 2 = 850 will also work Since time1 + time2 = 8 hours, then we can say: time2 = 30 ÷ (bv + 5) -10,200 + 850 pv = 9,000 + 750 pv Example: [ 30 • (bv -5) ÷ (bv + 5) ] = 8bv -70 Wind (or Current) Velocity   5 A plane's velocity in still air is 210 miles per hour. Distance 2   675 Airplane Velocity   440 Airplane (or Boat) Velocity   10 Example: (entering Time 1 = 6   Time 2 = 5 will also work) If you want the complete explanation (the solution that algebra teachers like), then just keep reading. 8bv² -60bv -200 = 0 When using this method, make sure distance1 is greater than distance2. time2 = 30 ÷ (bv + 5) Distance 2   675 [(850 × 12) + (750 × 12)] ÷ (850 -750) = plane velocity 120 devided by 60 is 2, so our speed number is 2. D) Solving for Wind Velocity given Airplane Velocity and Distance. We only know the total time, so any equations we write must take that into account. When using this method, make sure distance1 is greater than distance2. When using this method, make sure distance1 is greater than distance2. [ 30 ÷ (bv - 5) ] + [ 30 ÷ (bv + 5) ] = 8 (725 × 210) - (725 × wind velocity) = (675 × 210) + (675 × wind velocity) Calculate your offset: (see above chart for 45 degrees} - I use wind speed/10 X distance to the pin for "laydown" head/tail and pure crosswinds. Enter Temperature (OAT) °F °C. Distance = velocity * time Going upstream, the time would be: What is the wind velocity? 4*plane vel + 160 = 4.5 * plane vel - 180 One thing we do know is that the total time equals 8 hours. You take a round-trip on an airplane, that has a velocity in still air of 440 mph. Since time is the same for both cases we can set up 2 "distance ÷ rate" fractions that equal each other. If the wind speed is x, and the difference between wind direction and runway heading is y, then the crosswind component is x sin(y) (and the headwind is x cos(y)).Modelling that in Excel would be pretty straightforward for all possible runway headings and wind velocities: you'd create . Distance = (400) * 6 Since it's a round trip, the distance is the same so: Airplane (or Boat) Velocity   10 05 Dec 2006, 14:31 DTC. We are not given a specific amount of time, but we do know that time = distance ÷ rate There are 2 ways to do this. Now, add two: 3 + 2 = 5. Each day, a boat makes a 30 mile trip upstream and 30 miles downstream, taking 8 hours for the round trip. When using this method, make sure distance1 is greater than distance2. [(850 × 12) + (750 × 12)] ÷ (850 -750) = plane velocity 850 ÷ (plane velocity + 12) = 750 ÷ (plane velocity - 12) You can easily determine the trigonometric Sine of an angle using your Windows or phone calculator - just go to the Scientific View. 3) 140 km/h. Distance   2400 The wind velocity is 12 miles per hour. Wind Velocity   40 Time   8 F) Solving for Boat Velocity when given Current Velocity, Distance and Time. We'll also abbreviate plane velocity and wind velocity as pv and wv. Multiplying both sides by (bv -5) Clicking "Calculate" we see the answer is: We only know the total time, so any equations we write must take that into account. plane velocity = 192 Clicking "Calculate" we see the answer is: Time   8 We only know the total time, so any equations we write must take that into account. Distance (return) = (440 + wind velocity) * 5 Time 2   4.5 Multiplying both sides by (bv -5) If you want the complete explanation (the solution that algebra teachers like), then just keep reading. When using this method, make sure distance1 is greater than distance2. Airplane Velocity   192 Insert the numbers from the problem into this equation: plane velocity = 192 The shorter method: Insert the numbers from the problem into this equation: We are not given a specific amount of time, but we do know that time = distance ÷ rate 30 + [ 30 • (bv -5) ÷ (bv + 5) ] = 8bv -40 Clicking "Calculate" we see the answer is: Going upstream, the time would be: plane velocity = 192 Since time is the same for both cases we can set up 2 "distance ÷ rate" fractions that equal each other. Wind Velocity   12 Example: Example: Clicking "Calculate" we see the answer is: Otherwise scroll to "the shorter method". The wind velocity is 12 miles per hour. (850 × -12) + 850 pv = (750 × 12) + 750 pv Distance1 ÷ (plane velocity + wind velocity) = Distance2 ÷ (plane velocity - wind velocity) 30bv -150 = 8bv² -70bv +40bv -350 Example: Wind (or Current) Velocity   5 Example: Insert the numbers from the problem into this equation: (850 × -12) + 850 pv = (750 × 12) + 750 pv Since time is the same for both cases we can set up 2 "distance ÷ rate" fractions that equal each other. Airplane (or Boat) Velocity   10 [ 30 ÷ (bv - 5) ] + [ 30 ÷ (bv + 5) ] = 8 Going upstream, the time would be: (850 × -12) + 850 pv = (750 × 12) + 750 pv Distance (out) = (440 - wind velocity) * 6 F) Solving for Boat Velocity when given Current Velocity, Distance and Time. Putting this value into this equation: [(725 × 210) -(675 × 210)] ÷ (725 + 675) = wind velocity Wind (or Current) Velocity   5 You take a round-trip on an airplane, that has a velocity in still air of 440 mph. 10,500 = 1,400 wind velocity Distance 1   850 Distance   30 Distance (return) = (440 + wind velocity) * 5 Airplane Velocity   575 F) Solving for Boat Velocity when given Current Velocity, Distance and Time. Using the calculator, we click "F" then enter Airplane Velocity   192 We only know the total time, so any equations we write must take that into account. It is output once these three inputs are completed using Equation 1, where V LS and V REF are interpolated . Distance 2   675 (152,250 -141,750) ÷ 1,400 = wind velocity Time 1   5 plane velocity = 192 (440 - wind velocity) * 6 = (440 + wind velocity) * 5 We'll also abbreviate plane velocity and wind velocity as pv and wv. In the example, 030 - 010 = 20°. 152,250 - 141,750 = 1,400 wind velocity 10,500 = 1,400 wind velocity (725 × 210) - (725 × wind velocity) = (675 × 210) + (675 × wind velocity) boat velocity = 10 miles per hour, Distance1 ÷ (plane velocity + wind velocity) = Distance2 ÷ (plane velocity - wind velocity) Insert the numbers from the problem into this equation: What is the boat velocity? psa +ws = 600 Without using the calculator Wind chill cannot be accurately calculated for outside air temperatures (OAT) greater that 50 °F (10 °C) and wind speeds less than 4 MPH (3.5 Knots). The shorter method: Going downstream, the time would be: We know that time = distance ÷ velocity. Going downstream, the time would be: Collecting the terms Using the calculator, we click "E" then enter What is the boat velocity? time2 = 30 ÷ (bv + 5) Entering Distance 1 = 750 and Distance 2 = 850 will also work Don't forget to change back to Full or you'll be chipping a 200 yard shot. Using the calculator, we click "F" then enter Clicking "Calculate" we see the answer is: Clicking "Calculate" we see the answers are: (850 ÷ 750) = [(plane velocity + 12) ÷ (plane velocity - 12)] DA40 XLT ; Max. Since time is the same for both cases we can set up 2 "distance ÷ rate" fractions that equal each other. So, what I'm asking is an introduction on how to convert a formula to use in caliber. There are 2 ways to do this. We only know the total time, so any equations we write must take that into account. Wind Velocity   12 We only know the total time, so any equations we write must take that into account. Distance   30 100 pv = 19,200 We know that time = distance ÷ velocity. Since time1 + time2 = 8 hours, then we can say: Flying the 747 and our FCOM and current version of FCTM still shows max of ref and 20. Collecting the terms Multiplying both sides by (bv +5) Going upstream, the time would be: Here is a method an E6B computer might use to calculate crosswind. Distance = velocity * time The top line is the 'actual' wind i.e. (725 × 210) - (675 × 210) = (725 × wind velocity) + (675 × wind velocity) If you want the complete explanation (the solution that algebra teachers like), then just keep reading. The wind velocity is 12 miles per hour. Entering Distance 1 = 750 and Distance 2 = 850 will also work (850 ÷ 750) = [(plane velocity + 12) ÷ (plane velocity - 12)] Time   8 When using this method, make sure distance1 is greater than distance2. Going downstream, the time would be: Distance = 2,400 850 ÷ (plane velocity + 12) = 750 ÷ (plane velocity - 12) Time 1   5 It flies for 725 miles with the wind and in the same amount of time, it flies 675 miles against the wind. Clicking "Calculate" we see the answer is: We are not given a specific amount of time, but we do know that time = distance ÷ rate (725 ÷ 675) = (210 + wind velocity) ÷ (210 - wind velocity) The shorter method: (725 × 210) - (725 × wind velocity) = (675 × 210) + (675 × wind velocity) We know that time = distance ÷ velocity. Using the calculator, we click "D" then enter (plane vel + 40) * 4 = (plane vel - 40) * 4.5 Airspeed Conversions (CAS/EAS/TAS/Mach) Convert between Calibrated Airspeed (CAS), Equivalent Airspeed (EAS), True Airspeed (TAS) and Mach number (M) using the tool below. Speed-Calculator. Collecting the terms 10,500 ÷ 1,400 = wind velocity (850 × -12) + 850 pv = (750 × 12) + 750 pv Caution Yellow 145-182 MPH Range of speed at which the aircraft should be operated only in smoothair, and then only with caution.     1728 Software Systems. What is the boat velocity? Clicking "Calculate" we see the answer is: Wind Velocity     25 The velocity of the current is 5 miles per hour. Distance   2880, Without using the calculator: 10,500 ÷ 1,400 = wind velocity Example: Time   8 30bv -150 = 8bv² -70bv +40bv -350 Going downstream, the time would be: Going upstream, the time would be: 8bv² -60bv -200 = 0 Crosswind limits are maximum demonstrated. Example: F) Solving for Boat Velocity when given Current Velocity, Distance and Time. 850 ÷ (plane velocity + 12) = 750 ÷ (plane velocity - 12) 100 pv = 19,200 [(850 × 12) + (750 × 12)] ÷ (850 -750) = plane velocity Without using the calculator (adsbygoogle = window.adsbygoogle || []).push({}); Clicking "Calculate" we see the answers are: (entering Time 1 = 2.75   Time 2 = 3 will also work) pull out a ruler & measure the height of the flag stick - 7 feet tall see #1 above & use that instead of the 'box'], 3. [(850 × 12) + (750 × 12)] ÷ (850 -750) = plane velocity (850 ÷ 750) = [(plane velocity + 12) ÷ (plane velocity - 12)] Distance = (plane velocity + wind velocity) * time 850 ÷ (plane velocity + 12) = 750 ÷ (plane velocity - 12) [ 30 ÷ (bv - 5) ] + [ 30 ÷ (bv + 5) ] = 8 (725 × 210) - (725 × wind velocity) = (675 × 210) + (675 × wind velocity) The velocity of the current is 5 miles per hour. Collecting the terms 100 pv = 19,200 Distance 2   750 And if the wind is 60 degrees or more off the runway, the crosswind . F) Solving for Boat Velocity when given Current Velocity, Distance and Time. Multiplying both sides by (bv -5) Author aerotoolbox Posted on January 11, 2020 June 19, 2020 Categories Aeronautical Calculators Tags aeronautical calculator , calculator , crosswind , headwind , relative wind , vector Using the quadratic equation calculator time2 = 30 ÷ (bv + 5) time2 = 30 ÷ (bv + 5) This method is the most accurate and, in my opinion, most straightforward way to calculate a crosswind component in your head. Since this is a round trip, the distance is the same so: Using the calculator, we click "F" then enter wind velocity = 7.5 miles per hour Distance = 2,880 Distance (return) = (440 + wind velocity) * 5 Distance (out) = (440 - wind velocity) * 6 We know that time = distance ÷ velocity. speed (14,000 ft, MCP) 285 km/h TAS 1: 154 kts TAS 1: 263 km/h TAS Devide the XWC by your speed number. Since time1 + time2 = 8 hours, then we can say: Airplane Velocity   192 We'll also abbreviate plane velocity and wind velocity as pv and wv. Distance1 ÷ (plane velocity + wind velocity) = Distance2 ÷ (plane velocity - wind velocity) Distance1 ÷ (plane velocity + wind velocity) = Distance2 ÷ (plane velocity - wind velocity) Using the calculator, we click "B" then enter 4*plane vel + 160 = 4.5 * plane vel - 180 boat velocity = 10 miles per hour, The shorter method: 30bv -150 = 8bv² -70bv +40bv -350 (10,200 + 9,000) ÷ 100 = plane velocity 10,500 ÷ 1,400 = wind velocity Using the calculator, we click "F" then enter Wind Velocity   12 (plane vel + 40) * 4 = (plane vel - 40) * 4.5 What is the airplane velocity? Going upstream, the time would be: [ 30 ÷ (bv - 5) ] + [ 30 ÷ (bv + 5) ] = 8 7) remain the same. Approach Speed Calculator. Airplane (or Boat) Velocity   10 Distance = (440 - 40) * 6 What is the boat velocity? Since it's a round trip, the distance is the same so: 340 = .5 * plane velocity Crosswind Takeoff •Low speed/weight controllability most affected •Tire side force capability limits crosswind -Side force affected by - Runway surface and contamination - Aft CG and lower GW •Engine inlet distortion—high bypass ratio engines -Effect of crosswind entering nacelle turns airplane downwind -Most noticeable on 777 wind velocity = 7.5 miles per hour Clicking "Calculate" we see the answer is: winds are 270 at 10 Kt., follow the 30̊ line down to 10 knots on the arc). Using the calculator, we click "E" then enter There are 2 ways to do this. 4. The velocity of the current is 5 miles per hour. Wind Velocity   40 Going downstream, the time would be: [ 30 ÷ (bv - 5) ] + [ 30 ÷ (bv + 5) ] = 8 440 = 11*wv The velocity of the current is 5 miles per hour. - that  point is 20 feet. Clicking "Calculate" we see the answers are: 30 + [ 30 • (bv -5) ÷ (bv + 5) ] = 8bv -40 ‎Good morning Captain, Thank you to the more than 2000 pilots now making consistently safe landings, specially with gusty winds. Clicking "Calculate" we see the answer is: 30bv -150 = 8bv² -70bv +40bv -350 [ 30 ÷ (bv - 5) ] + [ 30 ÷ (bv + 5) ] = 8 Clicking "Calculate" we see the answer is: [(850 × 12) + (750 × 12)] ÷ (850 -750) = plane velocity Distance = (440 - 40) * 6 This easy-to-use calculator is perfect for determining crosswind and headwind components just before takeoff or landing. We now calculate the crosswind and headwind (tailwind) speeds using the angle α and METAR information: Crosswind speed = wind speed * sin ( α ) Headwind speed (or tailwind) = wind speed * cos ( α ) One thing we do know is that the total time equals 8 hours. It flies for 725 miles with the wind and in the same amount of time, it flies 675 miles against the wind. [(725 × 210) -(675 × 210)] ÷ (725 + 675) = wind velocity Since time is the same for both cases we can set up 2 "distance ÷ rate" fractions that equal each other. Multiplying both sides by (bv +5) The list of features include: List of features Basic calculator . An internal combustion engine is designed to convert the reciprocating motion of the pistons into rotational motion at the crankshaft. time2 = 30 ÷ (bv + 5). Multiplying both sides by (bv +5) Distance 2   675 What is the airplane velocity? The first line assumes a 45 degree wind, if the wind isn't 45 degrees you have to adjust the calculation, but as we only need to consider a quarter of a circle (as the other three quarters are exactly the same maths just different directions), the adjustment isn't too much. Clicking "Calculate" we see the answer is: 8bv² -60bv -200 = 0 Wind (or Current) Velocity   5 (725 ÷ 675) = (210 + wind velocity) ÷ (210 - wind velocity) (725 × 210) - (675 × 210) = (725 × wind velocity) + (675 × wind velocity) We'll also abbreviate plane velocity and wind velocity as pv and wv. 10,500 = 1,400 wind velocity 100 pv = 19,200 (850 × -12) + 850 pv = (750 × 12) + 750 pv Since time is the same for both cases we can set up 2 "distance ÷ rate" fractions that equal each other. 8bv² -60bv -200 = 0 The wind velocity is 12 miles per hour. D) Solving for Wind Velocity given Airplane Velocity and Distance. Entering Distance 1 = 675 and Distance 2 = 725 will also work Collecting the terms The aerodynamic lift force depends on the airspeed and . (850 ÷ 750) = [(plane velocity + 12) ÷ (plane velocity - 12)] Insert the numbers from the problem into this equation: We'll also abbreviate plane velocity and wind velocity as pv and wv. Example: (850 × -12) + 850 pv = (750 × 12) + 750 pv Each day, a boat makes a 30 mile trip upstream and 30 miles downstream, taking 8 hours for the round trip. A plane flies for 850 miles with the wind and in the same amount of time, it flies 750 miles against the wind. D) Solving for Wind Velocity given Airplane Velocity and Distance. Example: It flies for 725 miles with the wind and in the same amount of time, it flies 675 miles against the wind. This conversion of temperature is made using the formula Celsius = (5/9)* (Fahrenheit-32); Enter °C. Calculate Wind Correction Angle Excel. We only know the total time, so any equations we write must take that into account. V NO 125 KIAS Maximum Structural Cruising speed. Distance = 720 * 4 Multiplying both sides by (bv +5) 270 is the wind direction, 230 is the runway alignment, the angle is 40). [ 30 • (bv -5) ÷ (bv + 5) ] = 8bv -70 The wind coverage has been calculated for a hypothetical aircraft with a maximum crosswind speed of 8 m/s. When using this method, make sure distance1 is greater than distance2. We'll also abbreviate plane velocity and wind velocity as pv and wv. We are not given a specific amount of time, but we do know that time = distance ÷ rate What is the boat velocity? 30bv -150 = 8bv² -70bv +40bv -350 10,500 = 1,400 wind velocity A plane flies for 850 miles with the wind and in the same amount of time, it flies 750 miles against the wind. Wind Velocity   7.5 Distance 1   850 Multiplying both sides by (bv +5) time1 = 30 ÷ (bv - 5) Time 1   5 Distance = (plane velocity + wind velocity) * time Without using the calculator 15). 2*psa = 1150 One thing we do know is that the total time equals 8 hours. When using this method, make sure distance1 is greater than distance2. When using this method, make sure distance1 is greater than distance2. On take-off and landing, crosswinds are difficult, so all aircraft have a "max allowed crosswind" speed that is indicated in the pilots operation handbook (i.e., the instruction manual). time2 = 30 ÷ (bv + 5) Wind Velocity   12 (725 ÷ 675) = (210 + wind velocity) ÷ (210 - wind velocity) Collecting the terms Distance 2   750 8) increase. There are 2 ways to do this. This is slightly conservative, but who cares on short finals. Multiplying both sides by (bv -5) [ 30 • (bv -5) ÷ (bv + 5) ] = 8bv -70 Further it is possible to calculate the flight time (TL) for a distance in dependance of groundspeed. For a heading (H), wind direction (D) and wind speed (S), the crosswind component© can be found with: Distance1 ÷ (plane velocity + wind velocity) = Distance2 ÷ (plane velocity - wind velocity) Distance1 ÷ (plane velocity + wind velocity) = Distance2 ÷ (plane velocity - wind velocity) Using the quadratic equation calculator Distance   1650 8bv² -60bv -200 = 0 From ther, it's a pretty easy guess to find 15 yards. Multiplying both sides by (bv -5) (850 × -12) + 850 pv = (750 × 12) + 750 pv [(850 × 12) + (750 × 12)] ÷ (850 -750) = plane velocity [ 30 • (bv -5) ÷ (bv + 5) ] = 8bv -70 Multiplying both sides by (bv -5) Then multiply the wind speed by the difference in wind direction: 5 x 1.5 = 7.5. About Topgolf Entertainment Group When using this method, make sure distance1 is greater than distance2. Distance = 2,880 Time 1   5 boat velocity = 10 miles per hour, Example: Be safe.Good morning Captain,Thank you to the more than 2000 pilots now making consistently safe landings, specially with gusty winds.This tool allows you to calculate a safe Approach Speed for your next landing. Collecting the terms (725 × 210) - (675 × 210) = (725 × wind velocity) + (675 × wind velocity) We know that time = distance ÷ velocity. Wind Chill. On the return trip, the airplane flies against a 40 mph wind and takes 4.5 hours to make the trip. (plane vel + 40) * 4 = (plane vel - 40) * 4.5 Insert the numbers from the problem into this equation: Using the quadratic equation calculator easy!Our goal is to prevent landing related incidents such as tail strikes, hard landings or hydroplaning by providing accurate calculations of optimum landing speeds for your jet aircraft.Enjoy! E) Solving for Plane Velocity given Wind Velocity and Distance. Collecting the terms 30bv -150 = 8bv² -70bv +40bv -350 Insert the numbers from the problem into this equation: Distance = 720 * 4 30 degrees off = 30 out of 60 minutes is half, so 50% of the wind. If you want the complete explanation (the solution that algebra teachers like), then just keep reading. The figures provided here are a very rough estimate. Multiplying both sides by (bv +5) (850 ÷ 750) = [(plane velocity + 12) ÷ (plane velocity - 12)] Insert the numbers from the problem into this equation: what the wind meter tells you. Wind Velocity   12 We'll also abbreviate plane velocity and wind velocity as pv and wv. What is the boat velocity? 30bv -150 = 8bv² -70bv +40bv -350 05 Dec 2006, 14:31 DTC. The shorter method: Since time1 + time2 = 8 hours, then we can say: [ 30 ÷ (bv - 5) ] + [ 30 ÷ (bv + 5) ] = 8 Example: Wind Direction: 190. 10,500 ÷ 1,400 = wind velocity According to Wayne, if you're shooting 180-grain .30/06 bullets at 2,700 fps, and the wind is coming at 10 mph from a right angle, allow 1 inch at 100 yards, 2 inches at 200, 6 inches at 300, and 12 inches at 400. Put a decimal in front of that number and add 0.2. Using the quadratic equation calculator Putting this value into this equation: The velocity of the current is 5 miles per hour. (152,250 -141,750) ÷ 1,400 = wind velocity Without using the calculator There are 2 ways to do this. When using this method, make sure distance1 is greater than distance2. Distance = velocity * time Airplane Velocity   210 Airplane Velocity   210 [ 30 • (bv -5) ÷ (bv + 5) ] = 8bv -70 Using the calculator, we click "D" then enter Since time is the same for both cases we can set up 2 "distance ÷ rate" fractions that equal each other. Insert the numbers from the problem into this equation: There are 2 ways to do this. 360 - 310 = 50 (wind angle) Now drop the zero = 5 and add 0.2. The greatest crosswind available. Without using the calculator Airplane (or Boat) Velocity   10 We know that time = distance ÷ velocity. E) Solving for Plane Velocity given Wind Velocity and Distance. Example: Distance 2   750 Airplane (or Boat) Velocity   10 (440 - wind velocity) * 6 = (440 + wind velocity) * 5 F) Solving for Boat Velocity when given Current Velocity, Distance and Time. 4) 200 km/h. Distance = (plane velocity + wind velocity) * time plane velocity = 192 Each day, a boat makes a 30 mile trip upstream and 30 miles downstream, taking 8 hours for the round trip. This is great info but....How do I know where "23.66" is? [ 30 • (bv -5) ÷ (bv + 5) ] = 8bv -70 The cross-country navigation of an aircraft involves the vector addition of relative velocities since the resultant ground speed is the vector sum of the airspeed and the wind velocity. We know that time = distance ÷ velocity. 725 ÷ (210 + wind velocity) = 675 ÷ (210 - wind velocity) (850 × -12) + 850 pv = (750 × 12) + 750 pv I've copied this from someone (my apologies I forget who so cannot give credit). Since this is a round trip, the distance is the same so: 152,250 - 141,750 = 1,400 wind velocity [ 30 • (bv -5) ÷ (bv + 5) ] = 8bv -70

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